It took me about 2.5 hours to create the below 52 bit de Bruijn cycle during Monday night football on Oct 8, 2018 while watching Drew Brees break the all time passing yards (a lot of trial and error and just got lucky with some choices but it works perfectly - did several hours of testing and debugging later):

October 8, 2018 Larry Finley starting from scratch created a 6 bit non-repeating de Bruijn sequence in a 52 bit circular cycle:
0 0 0 0 0 0 1 1 1 1 1 1
0 0 0 1 1 0 1 0 0 0 1
0 0 1 1 0 0 1 0 1 1 1
0 0 1 1 1 0 1 1 0 1 1 1 1
0 1 0 1 1

Spectator cuts the 52 card deck as many times as they want and then from face down deck they deal 6 cards face down in a horizontal row on the table. The magician can identify the sixth card (the cards are not marked nor changed in any way from the manufacturer).

You must use a one-way backed deck.
You can use any stack memorization technique that you have mastered ie: Aronson, Tamariz, simple Bridge order, Ace thru King of each suit etc.
Place your mental stack position card in the appropriate place below.
Example your 22nd card is first, your 44th card is second, your 24th card is third and so on (for position 0 and 53 and greater - the problem 12 cards see the next paragraph, it is easily handled).
22 44 24 48 32 0 +1 +3 +7 +15 +31 +63
62 60 56 +49 +35 6 +13 26 52 40 +17
34 4 +9 +19 38 12 +25 50 +37 +11 +23
46 28 +57 +51 +39 14 +29 +59 54 +45 +27 +55 +47
30 +61 58 +53 +43
The positions that have a plus sign means the card is oriented normally in the deck whereas the non plus sign cards are oriented upside down in the deck (using a one way back design).

Place your memorized stack number card in the matching position above and for the odd ball 12 cards do the following:
Place your position card to the following position:
0=your stack position 2
53=your stack position 33
54=your stack position 41
55=your stack position 5
56=your stack position 16
57=your stack position 10
58=your stack position 8
59=your stack position 18
60=your stack position 20
61=your stack position 21
62=your stack position 42
63=your stack position 36

Aronson Stack cards are in my Yelnif 52 - 6 card sequence deck as follows:
AH 6S 3D QS 10D KC +JS +5C +3H +7D +4D +JD
9H 5S 8C +6D +10C AS +2D QH 9D 3C +3S
JH 2H +8D +7S 10H 5H +7H QC +4S +10S +8S
8H 7C +AC +2C +6H KD +4H +AD 2S +4C +5D +9S +9C
KH +QD 6C +JC +KS
Reminder: the positions that have a plus sign means the card is oriented normally in the deck whereas the non plus sign cards are oriented upside down in the deck (using a one way back design).

Note that 40 of the numbers are within the range 1-52 so we can plug our mem stack cards at those 40 places.
Now the challenge is to mentally associate the 12 invalid values (the 11 greater than 52 and the value 0) with the 12 missing mem stack numbers and plug them in at those places.
Below are some general memory tricks to help associate the problem 12 numbers with the 12 cards:.
0 plus 2=2 (maybe O-2 as in Oxygen)
53 minus 20=33 (just say to self 53 33)
54 switch digits=41 (think "car 54 where are you" police car 2 spades to dig up bodies)
55 minus 50=5 (55 just use one 5)
56 minus 40=16 (56 chevy's attractive to 16 year old boys)
57 minus 47=10 (57 chevy's have 10 inch tail fins)
58 minus 50=8 (58 chevy's have 8 tires (not true) but use for memory method)
59 minus 41=18 (59 chevy's have high hp for 18 yr olds)
60 minus 40=20 (must be 20 years old to drive '60 supersport)
61 minus 40=21 (must be 21 years old to drive '61 supersport)
62 minus 20=42 (the 62 year old has a 42 year old wife)
63 switch digits=36 (63 reverse digits to 36)
Then use the translated number to remember your stack position card.

I use Aronson so instead of doing memory translation twice in my head I use direct memory tricks for the problem 12 cards:
0=King of Clubs at north pole zero degrees
53=Jack of Clubs like 33
54=car 54 police 2 Spades in back of the car to dig up bodies
55=9 Shovels digging up speed limit sign
56=8 Clubs in back seat of a 56 chevy to prevent someone from stealing the car
57=Ace of Clubs pasted on Heinz 57 ketchup bottle and a club symbol plugging top opening
58=6 Clubs (3 or each side) on weird oval tail lights of 58 Chevy
59=Ace of Diamonds (Perry Mason 1959 Hans Breel is an Ace diamond cutter)
60=The 60 Minutes clock face has the 5 of Spades pasted on it
61=I graduated in 61 and the homecoming Queen had Diamonds on her neck
62=My wife graduated in '62 and had 9 suitors of her Heart (not true but mem trick)
63=Jack of Diamonds reverse of 36

Just to clarify the construction of the Yelnif 52 de Bruijn deck.
Below:
First column is DeBruijn physical position in Yelnif 52 deck.
Second column is the card to use from the position in your mental stack.
When performing: the DeBruijn 6 card binary value will equal your mental stack number with the exception of 12 values (see asterisks) which you will need to memorize.
1 22
2 44
3 24
4 48
5 32
6 2* (0=2)
7 1
8 3
9 7
10 15
11 31
12 36* (63=36)
13 42* (62=42)
14 20* (60=20)
15 16* (56=16)
16 49
17 35
18 6
19 13
20 26
21 52
22 40
23 17
24 34
25 4
26 9
27 19
28 38
29 12
30 25
31 50
32 37
33 11
34 23
35 46
36 28
37 10* (57=10)
38 51
39 39
40 14
41 29
42 18* (59=18)
43 41* (54=41)
44 45
45 27
46 5* (55=5)
47 47
48 30
49 21* (61=21)
50 8* (58=8)
51 33* (53=33)
52 43

Orient the backs normally in the Yelnif 52 de Bruijn deck in physical positions:
7, 8, 9, 10, 11, 12, 16, 17, 19, 23, 26, 27, 30, 32, 33, 34, 37, 38, 39, 41, 42, 44, 45, 46, 47, 49, 51, 52
Orient the backs the reverse direction in the de Bruijn 52 deck in physical positions:
1, 2, 3, 4, 5, 6, 13, 14, 15, 18, 20, 21, 22, 24, 25, 28, 29, 31, 35, 36, 40, 43, 48, 50

More about the 12 odd ball values:
Example using the 37th card (physically in the de Bruijn 52 stack example):
37 10* (57=10)
When you are performing you will never see the binary total 10 come up within the six cards but you may see the total of 57 come up which you must translate in your head to your stack position 10 card. Just create a mnemonic story for each of the 12 numbers and its card. Note that these odd ball values are outside the normal range of 1-52 (53 thru 63 and 0) therefore they will not interfere with your normal 1-52 memorizations.

For the computer nerds out there: note that any 52 bit Debruijn non repeating 6 bit cycle will produce some values above 52 because the bit configuration 111 and 1111 (and some others) are legitimately needed in the low order bits to represent numbers 7, 15 etc. but when those bits cycle to the high order positions they become 56, 60 etc. Because of this there will be missing normal totals in the 1-52 range and that is what the 12 odd ball values are in my de Bruijn (calling it Yelnif 52) cycle.

Glowball,
This is your alter ego here. Your scheme means the first card of the six dealt could be worth 32, the second 16, and so on. How can I make your scheme work where the first card dealt could be worth 1 point, the second 2 points, the third 4 points, the fourth card 8 points etc and still have the bulk of the values point to my stack card numbers?

Easy, just construct your deck differently as shown below:

The below (using low to high 6 bit binary scheme) has the 12 bad numbers (those greater than 52 and 0) replaced with good numbers (ignoring the plus and minus signs this is the completed index to your stack positions):
-26, -13, -6, -3, -1, -2, +32, +48, +16, +20, +42, +9,
-31, -15, -7, +35, +49, -24, +44, -22, -11, -5, +34,
-17, -8, +36, +50, -25, -12, +38, -19, +41, +52, +4,
-29, -14, +39, +51, +10, -28, +46, +5, -27, +45, +37, +18, +21,
-30, +47, -23, +43, +33,
Note that the position numbers with the minus sign are the binary 0 cards whereas the ones with the plus sign are the binary 1 cards. Therefore orient the card backs that have the minus sign in the opposite direction from those with the plus sign.

Place your memorized stack number cards in the physical order shown in the index above thus giving you a 52 card DeDruijn 6 bit "low to high bit" deck.

Reminder that for the odd ball 12 cards when performing: if you get the odd ball value in the left column below then that means the sixth card is your stack value card in the position indicated:
0=your stack position 2
53=your stack position 33
54=your stack position 37---
55=your stack position 5
56=your stack position 16
57=your stack position 10
58=your stack position 4---
59=your stack position 18
60=your stack position 20
61=your stack position 21
62=your stack position 42
63=your stack position 9---

Create your own mnemonics to remember these 12 odd ball values and the cards associated with them.
Low to high binary scheme note: the 3 dashes --- for positions 54, 58 and 63 are just to let you know the only ones of the odd ball 12 that are different from the high to low binary scheme odd ball 12.

Note: because we are using the same 52 bit binary pattern for the low to high binary scheme the card's back positions to orient one direction and those to orient the opposite direction are exactly the same as in the high to low binary scheme (but there are different cards sitting in those positions).

If using Aronson memorized values then below is the DeBruin 52 card sequence to use (using low to high 6 bit scheme):
-QH, -2D, -AS, -5C, -JS, -KC, +10D, +QS, +8C, +5S, +9H, +8D,
-4D, -7D, -3H, +10C, +6D, -3D, +6S, -AH, -10S, -9S, +JH,
-3S, -6C, +JD, +QC, -7H, -5H, +10H, -7S, +2S, +9D, +2H,
-4H, -KD, +6H, +2C, +AC, -7C, +8H, +9S, -5D, +4C, +4S, +AD +QD,
-KH, +9C, -8S, +KS, +JC

Correction: my last post (about the low to high binary scheme) I had one bug having mem position 5 listed twice.
The below has the "+5" corrected to "+40"
The 55= line corrected to say: "55=your stack position 40"
The Aronson line corrected from "+9S" to "+3C".
I did a test run just now through all 52 combinations of 6 cards below and it is perfect now, sorry for the mistake.

The below (using low to high 6 bit binary scheme) has the 12 bad numbers (those greater than 52 and 0) replaced with good numbers (ignoring the plus and minus signs this is the completed index to your stack positions):
-26, -13, -6, -3, -1, -2, +32, +48, +16, +20, +42, +9,
-31, -15, -7, +35, +49, -24, +44, -22, -11, -5, +34,
-17, -8, +36, +50, -25, -12, +38, -19, +41, +52, +4,
-29, -14, +39, +51, +10, -28, +46, +40, -27, +45, +37, +18, +21,
-30, +47, -23, +43, +33,
Note that the position numbers with the minus sign are the binary 0 cards whereas the ones with the plus sign are the binary 1 cards. Therefore orient the card backs that have the minus sign in the opposite direction from those with the plus sign.

Place your memorized stack number cards in the physical order shown in the index above thus giving you a 52 card DeDruijn 6 bit "low to high bit" deck.

Reminder that for the odd ball 12 cards when performing: if you get the odd ball value in the left column below then that means the sixth card is your stack value card in the position indicated:
0=your stack position 2
53=your stack position 33
54=your stack position 37---
55=your stack position 40---
56=your stack position 16
57=your stack position 10
58=your stack position 4---
59=your stack position 18
60=your stack position 20
61=your stack position 21
62=your stack position 42
63=your stack position 9---

Create your own mnemonics to remember these 12 odd ball values and the cards associated with them.
Low to high binary scheme note: the 3 dashes --- for positions 54, 58 and 63 are just to let you know the only ones of the odd ball 12 that are different from the high to low binary scheme odd ball 12.

Note: because we are using the same 52 bit binary pattern for the low to high binary scheme the card's back positions to orient one direction and those to orient the opposite direction are exactly the same as in the high to low binary scheme (but there are different cards sitting in those positions).

If using Aronson memorized values then below is the DeBruin 52 card sequence to use (using low to high 6 bit scheme):
-QH, -2D, -AS, -5C, -JS, -KC, +10D, +QS, +8C, +5S, +9H, +8D,
-4D, -7D, -3H, +10C, +6D, -3D, +6S, -AH, -10S, -9S, +JH,
-3S, -6C, +JD, +QC, -7H, -5H, +10H, -7S, +2S, +9D, +2H,
-4H, -KD, +6H, +2C, +AC, -7C, +8H, +3C, -5D, +4C, +4S, +AD +QD,
-KH, +9C, -8S, +KS, +JC

Below is my corrected mnemonic stories (for the binary low to high) for the odd ball 12 DeBruijn 52 Aronson numbers:
0=King of Clubs at north pole zero degrees
53=broken 53 Chevy Jack up car with club
54=car 54 police 4 Spades in back of the car
55=3 Clubs beating on 55 speed limit sign
56=8 Clubs in back seat of a 56 chevy to prevent someone from stealing the car
57=Ace of Clubs pasted on Heinz 57 ketchup bottle
58=2 Hearts kissing on trunk of weird oval tail lights of 58 Chevy
59=Ace of Diamonds (Perry Mason 1959 Hans Breel is an Ace diamond cutter)
60=The 60 Minutes clock face has the 5 of Spades pasted on it
61=I graduated in 61 and the homecoming Queen had Diamonds on neck
62=My wife graduated in '62 and had 9 suitors of her Heart (not true but mem trick)
63=8 of Diamonds 63 year old Diamond smuggler ate his many Diamonds

There are much better deBruijns on other threads. This is a 24,28 deBruijn which will work fine on one way backs but it's better to be in the habit of using a 26,26 deBruijn sequence because you might want to use the red suit cards as binary "1"s in the future and rearrange your stack accordingly. So I am criticizing myself here since I'm the only one posting on this thread.

Another criticism of the above stack: it only gets you the identity of one card and since this stack is not a common mem stack, you have no easy way of identifying the other five cards, yuck. This means you need to have a cheat sheet to identify the other five cards and if you're going to need a cheat sheet you may as well keep your mem stack in tact and just have a cheat sheet for it and use six bit binary patterns from a 52-bit deBrujn so that once you have one card identified you will know the other five from memory.

Below is a much better deBruijn that I call jmbulg-B therefore use your pristine stack and a one way deck and orient each card position appropriately then when the six cards are dealt on a table the magician can get the identity of the first card from the binary pattern and then instantly knows the other five cards from memory.

jmbulg-B deBruijn:
0, 0, 1, 1, 0, 1, 1, 0, 0, 1, 0, 0, 1, 0, 1, 0, 1, 0, 0, 1,
1, 0, 0, 0, 0, 0, 1, 1, 1, 0, 1, 0, 0, 0, 1, 0, 1, 1, 0, 1,
0, 1, 1, 1, 0, 0, 1, 1, 1, 1, 1, 0

When you look at the six cards separate them in your mind into two groups of three. The first group of three make up the first octal digit. The second group of three makeup the second octal digit.

Example: 101010 becomes in your mind 101 010 and then becomes in your mind 5 2.

Now that you have the two octal digits just quickly look down the cheat sheet list until you see the same two digit octal code (the list is in numeric order so it should be easy to spot the proper row). In this example the 52 tells you that the first card of the six is your mem stack card in position 13. Then you know the other five cards from memory.

One screen jmbulg-B 6 card 1 way generic Cheat Sheet A list:
01 pos 22 ... 40 pos 21
03 pos 23 ... 42 pos 31
05 pos 32 ... 43 pos 51
06 pos 52 ... 44 pos 7
07 pos 24 ... 45 pos 10
11 pos 8 .... 46 pos 17
12 pos 11 ... 47 pos 44
13 pos 33 ... 50 pos 29
14 pos 18 ... 51 pos 15
15 pos 1 .... 52 pos 13
16 pos 25 ... 53 pos 38
17 pos 45 ... 54 pos 4
21 pos 30 ... 55 pos 35
22 pos 9 .... 56 pos 40
23 pos 16 ... 60 pos 20
24 pos 14 ... 61 pos 50
25 pos 12 ... 62 pos 6
26 pos 34 ... 63 pos 43
27 pos 39 ... 64 pos 28
30 pos 19 ... 65 pos 37
31 pos 5 .... 66 pos 3
32 pos 36 ... 70 pos 49
33 pos 2 .... 71 pos 42
34 pos 41 ... 72 pos 27
35 pos 26 ... 74 pos 48
37 pos 46 ... 76 pos 47

This type of cheat sheet keeps your mem stack intact which makes everything easier.

See below thread which is essentially the same as this better method, but the below thread also describes using a little circle or thumbprint at the bottom on the face of each card to allow spectators to hold the card in front of them and the magician be sure they've kept the one way orientation properly.

https://www.themagiccafe.com/forums/view......orum=205

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