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Topic: Cool ways to figure out someone's Phone Number
Message: Posted by: drkptrs1975 (May 23, 2005 12:59PM)
Show them four cards, one at a time.

First Card ( 9 , 8) then ask them to tell you what numbers they see. (Add up 8 in whatever digit they say)

Then with next Card ( 4,5,6,7) ask them same question. (add 4 to the digits they say)

Next Card ( 2,3,6,7) (add 2 )

Next Card (1,3,5,7,9) (add 1)

That will then give you their 7 digit phone number


The second way is give them a calculator

1. press the first 3 digits
2. Multiply by 80
3. Add 1
4. Multiply by 250
5. Now Add the next 4 digits
6. Add then agian
7. Subtract 250

8 have them tell you the results
9. Divide by 2, that will give you their phone number.
Message: Posted by: Dennis Loomis (May 24, 2005 06:37PM)
I can't seem to follow this. In the first effect, I don't know what's on the cards and what "add up 8 in whatever digit they say: means.

The second one, I can follow up to step 6. That seems to suggest you do step five again. But the answer is not the phone number I started with.

Can you clarify, perhaps with a specific example of a phone number and what you do at each step?

Dennis Loomis
Message: Posted by: stanalger (May 24, 2005 07:52PM)
Perhaps an example would clear things up.

Derek has four cards. The first has the numbers 9 and 8 printed on it.
The second has 7, 6, 5, and 4 printed on it. The third: 2, 3, 6, 7.
The fourth: 1, 3, 5, 7, 9.

Suppose my phone number is 662-3727. When Derek shows me the first card,
I tell him I don't see [b]any[/b] of the digits in my number on the card.

When he shows me the second card, I tell him that I see my 1st, 2nd, 5th
and 7th digits. (Since the 1st, 2nd, 5th, and 7th digit of my phone #
are 6, 6, 7, 7 and these [b]are[/b] on the second card.)

When he shows the third card, I tell him that I see [b]all[/b] seven of
the digits of my phone number.

Finally, he shows the fourth card and I tell him that I see my 4th, 5th, and
7th digits.

Derek then tells me my phone number.
Message: Posted by: stanalger (May 24, 2005 08:04PM)
[quote]
On 2005-05-23 13:59, drkptrs1975 wrote:

1. press the first 3 digits
2. Multiply by 80
3. Add 1
4. Multiply by 250
5. Now Add the next 4 digits
6. Add then agian
7. Subtract 250

8 have them tell you the results
9. Divide by 2, that will give you their phone number.

[/quote]

Suppose my number is 662-3727.
1. I enter 662 into the calculator.
2. Multiply by 80. (Calculator now reads 52960.)
3. Add 1. (52961)
4. Multiply by 250. (13240250)
5. Add 3727. (These are the next/last four digits of my #. Calculator reads:
13243977)
6. Add 3727 again. (Calculator: 13247704)
7. Subtract 250. (Calc: 13247454)


13247454 divided by two gives: 6623727, my phone number.
Message: Posted by: Watercooler (Jun 13, 2005 11:10AM)
Thanks for this drkptrs1975,
Is there a way to adapt the method for phone numbers with 8 digits?
Message: Posted by: stanalger (Jun 14, 2005 11:09AM)
Watercooler,

Derek's first trick works with 8 digit numbers as well.

In order to get the second trick to work with an 8 digit number, the first
step should be changed to "Enter the first 4 digits." Nothing else changes.
Message: Posted by: Watercooler (Jun 16, 2005 09:07AM)
Thanks, easy when you know how!
Message: Posted by: The Great Smartini (Jun 20, 2005 12:36AM)
Anyone follow the mathematic equation that occurs using the calculator...is there an algebraic formula?
Message: Posted by: James F (Jun 27, 2005 06:57PM)
Mathematically, its really just a simple algebra trick. (although very cool) Heres the algebraic formula:

we will call the first 3 digits 'a' and the last 4 digits 'b' We will call the answer (which is your number) 'x'

x = (80a + 1)250 + 2b - 250}/2

If you simplify this down you get

x = (20000a + 250 + 2b - 250)/2
x = (20000a + 2b)/2
x = 10000a + b

Which would give you your phone number.

Pretty much all you are doing is multiplying your first three digits by 10,000. This give you your first three digits with 4 zeros after it. Then all you have to do is add the last 4 and it completes your phone number. Hope that makes sense :)

James
Message: Posted by: itsmagic (Jun 29, 2005 09:57AM)
Very cool, thank you for sharing.
Message: Posted by: itsmagic (Jun 29, 2005 09:44PM)
Please clarify some more on the first method for this trick. I still cannot figure out that card example. What do you add to the cards shown?

As for the second method. Very nice. I love it. My co-workers love it too.
Message: Posted by: dr chutney (Jun 30, 2005 10:44AM)
Just to clarify the card method. This is similar to the binary counting card trick where the spec mentally chooses a card from any fifteen they deal themselves, and 'the computer' shuffles the cards four times, after which you reveal the card they had merely thought of.

Any way, back to the phone. Let's keep it at 7 digits, say 694 2869.

For each position start with a zero

000 0000

Now show the first card ( 9 8 )
They say they can see the second, fifth and seventh digits.
Add 8 into those positions and your running total reads
080 0808

Show the second card ( 4 5 6 7 )
They say they can see the first, third, and sixth digits.
Add 4 into those positions and your running total reads
484 0848

Show the third card ( 2 3 6 7 )
They say they can see the first, fourth, and sixth digits.
Add 2 into those positions and your running total reads
684 2868

Finally show the fourth card ( 1 3 5 7 9 )
They say they can see the second, and seventh digits.
Add 1 into those positions and your running total reads
694 2869

You have their number.
Message: Posted by: SteveFowkes (Jul 23, 2005 10:41AM)
For the second method using a UK telephone number (6 digits excluding area code), it can be worked one of two ways.
1) Use the method as it is but ignore the middle zero after dividing by two.
2) Modify the method so that the multiplication and subtraction is by 25 and not 250.
Message: Posted by: Slim King (Sep 3, 2005 06:55AM)
There is a cool method that I use on my radio show. I'll send emails with mp3's to anyone who wants it, as soon as the radio station sends me a copy. You'll like this one too.
Message: Posted by: Slim King (Sep 4, 2005 01:00PM)
Don't buy Dial M for Magic. I just did, and yes it can reveal a telephone number....IF IT"S NOT MORE THAN FOUR DIGITS!!!!!! I just wasted some more cash on something that promises one thing and doesn't deliver....Whew.....
Message: Posted by: McCritical (Jun 20, 2006 10:45PM)
[quote]
On 2005-05-23 13:59, drkptrs1975 wrote:
Show them four cards, one at a time.

First Card ( 9 , 8) then ask them to tell you what numbers they see. (Add up 8 in whatever digit they say)

Then with next Card ( 4,5,6,7) ask them same question. (add 4 to the digits they say)

Next Card ( 2,3,6,7) (add 2 )

Next Card (1,3,5,7,9) (add 1)

That will then give you their 7 digit phone number.
[/quote]

I've been screwing around with this a little and I hope you like it....

Pull 4 business cards out of your wallet or planner and toss them on the table.

First card: Infinity Data Systems, 900 Tower Drive, Henderson, Nevada 89009--Toll Free: (800) 998-0099

Second card: Quarterson Technology, 7745 North Harris, Gower, Missouri 64454--Local: 464-5477

Third card: Parity Electronics, 3200 Terrace Circle, Fairfax, Virginia 22037-- (276) 362-7300

Fourth card: Code One, 3115 McKinley Park, Galveston, Texas 77551--Phone: 1 (713) 395-9175

Try to keep attention directed on the phone numbers (although if the person's eyes wander to other numbers on the card, the trick should still work). Consider putting your finger over the area code to get them to focus on the 7 digit number, and for those living in areas with the 10 digit phone numbers, the principle should work too.

I tried to make it easy so the cards can be used in any order, Infinity = 8, Quarter = 4, Parity =2 and Code One = 1. That way you can begin with a card that has a wider range of numbers (like 1-3-5-7-9, or 2-3-6-7-0), point out the phone number on the card, ask innocently "think about the digits in this phone number...we have a two here, a six here, a three here, a zero here, and finally a seven. Do any of these numbers appear in your phone number?...etc." and then, because it's the "Parity" card, you simply add 2 to all the places where one of those digits are present.

What about the zero appearing in the phone numbers on the "Infinity" and "Parity" cards? Eight plus two equals ten--just make the digit a zero and don't carry the one.
Message: Posted by: Paradise (Jun 22, 2006 08:16AM)
[quote]
On 2005-06-30 11:44, dr chutney wrote:
Just to clarify the card method. This is similar to the binary counting card trick where the spec mentally chooses a card from any fifteen they deal themselves, and 'the computer' shuffles the cards four times, after which you reveal the card they had merely thought of.

Any way, back to the phone. Let's keep it at 7 digits, say 694 2869.

For each position start with a zero


This is a great method and thread, I have tried it with 11 didgit numbers and it works on those as well.

It should work on any amount shouldnt it?

000 0000

Now show the first card ( 9 8 )
They say they can see the second, fifth and seventh digits.
Add 8 into those positions and your running total reads
080 0808

Show the second card ( 4 5 6 7 )
They say they can see the first, third, and sixth digits.
Add 4 into those positions and your running total reads
484 0848

Show the third card ( 2 3 6 7 )
They say they can see the first, fourth, and sixth digits.
Add 2 into those positions and your running total reads
684 2868

Finally show the fourth card ( 1 3 5 7 9 )
They say they can see the second, and seventh digits.
Add 1 into those positions and your running total reads
694 2869

You have their number.




[/quote]
Message: Posted by: Paradise (Jun 22, 2006 08:21AM)
[quote]
On 2005-06-30 11:44, dr chutney wrote:
Just to clarify the card method. This is similar to the binary counting card trick where the spec mentally chooses a card from any fifteen they deal themselves, and 'the computer' shuffles the cards four times, after which you reveal the card they had merely thought of.

Any way, back to the phone. Let's keep it at 7 digits, say 694 2869.

For each position start with a zero



000 0000

Now show the first card ( 9 8 )
They say they can see the second, fifth and seventh digits.
Add 8 into those positions and your running total reads
080 0808

Show the second card ( 4 5 6 7 )
They say they can see the first, third, and sixth digits.
Add 4 into those positions and your running total reads
484 0848

Show the third card ( 2 3 6 7 )
They say they can see the first, fourth, and sixth digits.
Add 2 into those positions and your running total reads
684 2868

Finally show the fourth card ( 1 3 5 7 9 )
They say they can see the second, and seventh digits.
Add 1 into those positions and your running total reads
694 2869

You have their number.




[/quote]




This is a great method and thread, I have tried it with 11 didgit numbers and it works on those as well.

It should work on any amount shouldnt it?
Message: Posted by: Slim King (Jun 22, 2006 09:44AM)
Are these cards on the market or must I make my own?
Message: Posted by: McCritical (Jun 23, 2006 04:08PM)
[quote]
On 2006-06-22 10:44, Slim King wrote:
Are these cards on the market or must I make my own?
[/quote]

Make your own. Dressing up an effect should be fun. Try tailoring your "cards" to fit the performance. There are all sorts places to find inspiration...this thread for example: http://www.themagiccafe.com/forums/viewtopic.php?topic=151788&forum=99&9

Let's say you want to "explore" how well personal numbers (like birthdates, ID numbers, or phone numbers) fare in games of chance. You pull out a Cash 3 ticket with the numbers 9-8-9 (maybe even with a brief backstory on how it's the area code of an old girlfriend in Saginaw Michigan, giving you a "reason" for performing this experiment on the spectator's phone number). Ask him if any 8s or 9s appear in his phone number. Ask him where. Pull out a couple of Pick 4 tickets with 4-6-7-5 and 2-6-3-7 and ask, what are the [i]odds[/i] that these numbers appear in the spectator's phone number as well. Repeat the process for each of the Pick 4 tickets. Then...speaking of [i]odds[/i]...ask the spectator which digits in his number are [b][i]odd[/i][/b] numbers. Do the math for the first three "cards" and add 1 for the digits the spectator indicates are [i]odd[/i].

$3, 3 chances to win, and the losing tickets go into your wallet as props. [And to address something I wrote earlier...you can use the process to reveal someone's social security number, however, with all the worries about identity theft, a phone number is probably your safest bet.]