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Topic: Numbers juggling 


No, I'm not posting in the wrong forum; I'm sharing one of my original puzzles: This one should be solved by hand (pencil and paper). If you use computer software, you will be cheating yourself out of a pleasant surprise. Examine the following sum: 7CLUBS + 9BALLS = NUMBERS Math challenge: Produce a onetoone correspondence between the elements of the set {0, 1, 2, 3, 4, 5 ,6 ,7 ,8 ,9} and the elements of the set {C, L, U, B, S, N, A, M, E, R} so that when each letter in the sum is replaced with its corresponding digit, the result will be a valid base ten sum of two six digit numbers. Word challenge: Unscramble the ten different letters used in the sum to spell a familiar tenletter word. If you've solved both parts, post your solution to the word challenge in encoded form via the onetoone correspondence which solves the math challenge. **Please do not post partial solutions.**  For those not familiar with the jargon of the jugglers, "numbers juggling" once referred to the juggling of 5 or more objects. As more and more jugglers (both professional and recreational) became more and more proficient at keeping more objects in the air, the definition of "numbers juggling" began to change. Many ball jugglers didn't consider ball juggling to be "numbers juggling" unless at least 7 balls were involved. Juggling 5 clubs was still considered "numbers juggling" because juggling 5 clubs is more difficult than juggling 5 balls. And the jugglers continue to push the boundaries. Today, many would argue that "numbers juggling" should be reserved for 8 or more balls...and 6 or more clubs. It's certainly safe to say that most jugglers would agree that 9 balls or 7 clubs should still be considered "numbers juggling." Stan Alger 


6104739528 I must say that I missed the pleasant surprise but with all those things fitting together this puzzle seems like it was meant to be and I can't fathom how you came up with it. Absolutely unreal work, Stan. /Tomas 


Congratulations, Tomas! You made quick work of that one. I suppose this thread is finished. No need for any further posts. If any other wouldbe solvers get frustrated with a pencil and paper attack, anagram software (or an anagram dictionary) together with your 10 digit number will provide all answers. Stan 


But software/dictionary should only be used as a LAST RESORT. 


Stan, Nice puzzle. Thanks. I hadn't worked a cryptarithm in years. I would nominate 6105948273 as an alternate to Tomas's solution. leonard 


A second solution? Very good, leonard...and shame on me! I [b]thought[/b] I had been thorough in my search for solutions; obviously I was mistaken. I came up with this puzzle in the early 80's. It was published in _Juggler's World_. Leonard, you are the first to point out the nonuniqueness of the "solution." At about the same time, I came up with another cryptarithm with a juggling theme. It didn't have the added bonus that the letters could be rearranged to spell a tenletter word, but I think it [b]does[/b] have a unique solution. If the solution isn't unique, I'll bet leonard will find the alternate solution(s). Here it is: I * JUGGLE = PLATES (Juliet: Gasp! I must be spending too much time thinking about Stephen Buxton's puzzles. These ten letters also include P I E as well as P L A E. See Buxton's "Holiday Facts" and "Doors, Part Three.") Stan Alger 


Stan, I obtained only one solution this time (to the new puzzle). If I am correct, JUGGLE has 839 as a divisor. leonard 


Thanks, leonard. Now I feel more confident that I * JUGGLE = PLATES has a unique solution. My solution is buried in my apartment. (Water was leaking from the apartment above mine, so I had to quickly consolidate the contents of the wet rooms into the dry rooms. The dry rooms have boxes stacked high. Been living this way for several weeks now. Can't wait to get things back to normal.) 