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NJJ Inner circle 6437 Posts |
In Magic Magazine, September 2000, Bob Farmer has a great math scam in his book.
Four playing card dice are mixed under four cups. The victim picks one The magician picks another. the magician wins 2/3 of the time. He states that it uses transitive numbers and that Cup A will be beat Cup B 2/3 of the time. Cup B will be beat Cup C 2/3 of the time. Cup C will be beat Cup D 2/3 of the time. Cup D will be beat Cup A 2/3 of the time. The playing card dice are specially made with certain face values. I just don't see how this possible! Help! (please remember...I am an idiot!) |
stanalger Special user St. Louis, MO 998 Posts |
The dice are non-transitive.
If they were transitive then the fact that i) A beats B and ii) B beats C and iii) C beats D would necessarily mean that A beats all the others. We're all familiar with transitive relations: If Al is taller than Bob and Bob is taller than Carl, then Al must necessarily be taller than Carl. But not all relations are transitive. Google "non-transitive dice" and you'll get what you're looking for. |
NJJ Inner circle 6437 Posts |
Thanks!
(I told you I was stoopid!) Farmer had playing card dice which confused me further! http://www.grand-illusions.com/toyshop/ntdice1/ Hey! It's just like Rock Paper Scissors. |
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