

Roland Henning Special user Kiel, Germany 511 Posts 
SEND+MORE=MONEY
Different letters equal different digits. What are the numbers? 
blazes816 Special user Wichita, Kansas 522 Posts 
Can 2 letters be the same number?

blazes816 Special user Wichita, Kansas 522 Posts 
And is
SEND +MORE  MONEY the correct format? 
stanalger Special user St. Louis, MO 996 Posts 
95519 077 60 065'9 7065.
9015065 9006...259? 
Roland Henning Special user Kiel, Germany 511 Posts 
Same letter, same digit. different letter, different digit. BTW. There is only one solution.
If you add the numbers that make up Send and More, you'll get money. 
Roland Henning Special user Kiel, Germany 511 Posts 
Quote:
On 20050710 17:17, blazes816 wrote: The format doesn't matter. 
RiffClown Inner circle Yorktown, Virginia (Previously Germany) 1579 Posts 
PM'd you with the solution.
Rob "Riff, the Magical Clown" Eubank aka RiffClown
<BR>http://www.riffclown.com <BR>Magic is not the method, but the presentation. 
Roland Henning Special user Kiel, Germany 511 Posts 
Rob is right. The solution (and the way to that) will be posted later.

stanalger Special user St. Louis, MO 996 Posts 
If you know what number each letter represents
(and thus what letter each number represents), you can easily decode my earlier numerical post. 
Roland Henning Special user Kiel, Germany 511 Posts 
Okay, here the solution.
9567+1085=10652 Why? The terms of the sum have four digits. The sum has five digits. So M=1 that means that S must be either S=8 or S=9. So O can be O=1 or O=0, It cannot be O=1 because, then M and O would be both 1. The conditions don't allow that. That means O=0, which chancels the possibility of S=8. So S=9. Here is what follows. Try to not get confused. If D+E<10 (because E unequal N) then N+R10=E AND N=E+1 therefore E+1+R10=E ==> R=9 which is WRONG (S=9, not R) If D+E>10 then D+E10=Y, N+R9=E, N=E+1 therefore E+1+R9=E ==> R=8 which is POSSIBLE So far we got: M=1 O=0 S=9 R=8 D=Y+(10E) therefore (10E)< or equal 5, therefore E=5 OR E=6 If E=6, then N=7, D=Y+4 (Y=2, D=6 ==> WRONG, because E=6 not D) or (Y=3, D=7 ==> WRONG, because N=7 not D) If E=5, then N=6, D=Y+5 ==> Y=2, D=7 ==> POSSIBLE. M=1 O=0 S=9 R=8 E=5 N=6 Y=2 D=7 SEND + MORE = MONEY 9567 + 1085 = 10652 ==> TRUE, therefore the solution. 
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