

Scott Cram Inner circle 2677 Posts 
Your challenge, should you decide to accept it, is to create an equation with the following qualities:
1) The only mathematical functions allowed are addition and subtraction. 2) The equation must be written twice, once in numerical form, and once with the numbers spelled out as words. 3) In the "word equation", when the letters of each words are "added" (as in "ONE" plus "TWO" would equal "ONETWO") or "subtracted" (for example, "ZEROTEN" minus "ONE" would equal "ZERT" or "ZRTE") to the other words, the final result of all the additions and subtractions should be a word for a number. 4) The "word equation" and the "numerical equation" should result in the same number. I only know of one answer, but others may be possible. 
TomasB Inner circle Sweden 1143 Posts 
Sounds like a nice problem. Along the same lines as the anagram
eleven plus two = twelve plus one /Tomas 
Scott Cram Inner circle 2677 Posts 
I'd forgotten about that anagram. However, I should mention that the functions aren't spelled out in the word equation. They're performed as described above. In your example,
ELEVEN + TWO = ELEVENTWO Unfortunately, this wouldn't work because ELEVENTWO isn't a name for a real number. 
stanalger Special user St. Louis, MO 996 Posts 
Tomas is on the right track. A little rearranging of terms
gives: TWO + ELEVEN  ONE = TWELVE. (When subtracting ONE from TWOELEVEN, you have a choice as to which E is subtracted. Choose the second E.) 2+111=12 Stan Alger 
leonard Regular user North Carolina 143 Posts 
How about:
ONE HUNDRED ONE  ONE = ONE HUNDRED ONE HUNDRED TWO  TWO = ONE HUNDRED etc. Did I miss a rule? leonard 
leonard Regular user North Carolina 143 Posts 
Another one:
NINETEEN  SEVENTEEN  NINE + SEVEN + ONE = ONE Similar answers using other combinations of 14, 16, 17, 19, 4, 6, 7 and 9. 
Scott Cram Inner circle 2677 Posts 
Stan got the one I was shooting for, but I love the others by leonard as well. They qualify quite well.
Although for your latter one, Leonard, I would rephrase it as: SEVEN+NINETEENSEVENTEENNINE+ONE=ONE In your initial equation you technically can't take away SEVENTEEN from NINETEEN, since the letters are there at that point. Done as I just put it, however, it can work. As an added bonus, the numerical equation doesn't go into negative numbers. 
TomasB Inner circle Sweden 1143 Posts 
I think the solution you wanted is such a nice one that it is worth it to add further restraints of the original problem to force that solution. You want to avoid solutions such as TWENTYONEONE=TWENTY, TWENTYTWOTWO=TWENTY, ..., NINETYNINENINE=NINETY.
So I guess the new problem is: State the conditions to force the solution to be TWO + ELEVEN  ONE = TWELVE /Tomas 
leonard Regular user North Carolina 143 Posts 
Scott,
Nice puzzle. Thanks. And I agree totally with your restatement. Mathematically it doesn't matter, but within the parameters of the problem, rearrangement makes sense. Tomas, I agree. I haven't been able to come up with any useful conditions either. However, I am not sure there is not another "elegant" answer (i.e. I haven't given up yet). Scott, In the word equation, does the answer have to be in the correct order, or can the letters be rearranged? 
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