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magicjohn2278 Special user Isle of Man UK 544 Posts 
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Inspired by Nir's recent post...
I misread the question and tried to solve a different one, don't know whether my answer was right or wrong as I don't know much about permutations (or probability!) So... to check my answer here's the question: Coupons in cereal boxes are numbered 1 to 5, and a set of one of each is required for a prize. with one coupon per box, what is the easiest way to calculate the probability that someone buying just 5 boxes, will get the prize? |
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magicjohn2278 Special user Isle of Man UK 544 Posts
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What? ... No takers? I expected half of you to know this one!
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LobowolfXXX Inner circle La Famiglia 1196 Posts
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1 in 5!/5^5.
That is to say: 5/5*4/5*3/5*2/5*1/5, or 24/625.
"Torture doesn't work" lol
Guess they forgot to tell Bill Buckley. "...as we reason and love, we are able to hope. And hope enables us to resist those things that would enslave us." |
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magicjohn2278 Special user Isle of Man UK 544 Posts
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LobowolfXXX - Nice try, but which?
5/5*4/5*3/5*2/5*1/5 or 24/625....? |
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LobowolfXXX Inner circle La Famiglia 1196 Posts
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Quote:
On 2006-03-10 20:08, magicjohn2278 wrote: Ummmmm...same thing. Ignore 5/5; it doesn't change anything. Multiply the numerators: 4x3x2x1 = 24. Multiply the demoninators: 5x5x5x5 = 625.
"Torture doesn't work" lol
Guess they forgot to tell Bill Buckley. "...as we reason and love, we are able to hope. And hope enables us to resist those things that would enslave us." |
| The Magic Cafe Forum Index » » Puzzle me this... » » Coupons 2 (0 Likes) | |
Posted: Mar 10, 2006 06:00 pm 
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