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The Magic Cafe Forum Index » » Magical equations » » How does this work ? (0 Likes) Printer Friendly Version

DavidF
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Has anyone seen this web site ? http://digicc.com/fido/ Im sure there is a simple answer to this puzzle but I cannot work it out.I don't want the answer I would just like to know if anyone knows how it works
landmark
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Cute website. It's a very old math effect. I don't think anyone will mind if I tell you that when you do that kind of subtraction, the digits must add up to a multiple of nine. Lots of other fun math stuff in this forum, check it out.


Jack Shalom
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I do!
DW
Slim King
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Relax there Jack! That's my favorite secret...LOL
THE MAN THE SKEPTICS REFUSE TO TEST FOR ONE MILLION DOLLARS.. The Worlds Foremost Authority on Houdini's Life after Death.....
TomasB
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That is definitely my favourite way to force a number to be a multiple of nine.

Here's a hint to why it works (n>m): a*10^n-a*10^m=a*10^m(10^(n-m)-1)=9*a*10^m*111...111 where the last number has n-m ones in it.

/Tomas
landmark
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Quote:
Here's a hint to why it works (n>m): a*10^n-a*10^m=a*10^m(10^(n-m)-1)=9*a*10^m*111...111 where the last number has n-m ones in it.


That's easy for you to say . . . Smile
roi_tau
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What is it about the nine that so many tricks involve him.

will it work with 7 in a octali basis?


Have fun
ROi
Nir Dahan
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Quote:
On 2006-06-23 11:16, roi_tau wrote:
What is it about the nine that so many tricks involve him.

will it work with 7 in a octali basis?


Have fun
ROi


yes

Gardner (who else) has written about it.
N
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