|
|
|
|||
Nir Dahan Inner circle Munich, Germany 1390 Posts 
|
X^x^x^x^x .... = 2
how much is x? hint: it helps if you solve first x^x^x = 2 Nir Visit me at http://www.bidthegrid.com |
|
Scott Cram Inner circle 2678 Posts
|
X=1.28721218653
|
|
wildarr New user Isle of Palms, SC 80 Posts
|
X^x^x^... = x^(x^x^x^... )
Let y = x^x^x^... if the limit exists Then y = 2 so... x^(y) = 2 x^2 = 2 x = sqrt(2) Magic! |
|
Nir Dahan Inner circle Munich, Germany 1390 Posts
|
|
|
wildarr New user Isle of Palms, SC 80 Posts
|
Reminds me of the "What is the largest number you can write with 3 digits?" question. Do we dare post that?
Of course this is probably not the best (hint...hint...) place to post this.... |
| The Magic Cafe Forum Index » » Puzzle me this... » » Equation (0 Likes) | |
Posted: Jul 8, 2006 10:43 am 
| [ Top of Page ] |
|
All content & postings Copyright © 2001-2024 Steve Brooks. All Rights Reserved. This page was created in 0.01 seconds requiring 5 database queries. |
|
The views and comments expressed on The Magic Café are not necessarily those of The Magic Café, Steve Brooks, or Steve Brooks Magic. > Privacy Statement < 
|