

bobmcmathman New user Arizona 43 Posts 
Help!!! (Please)
I have performed Ammar's "Will the cards match" effect with business cards for several years for patients in the emergency room. They love it! Now, I am interviewing for a job later this week and would like to be able to perform for prospective employers. I have tried and tried and cannot come up with a phrase such as: Give Bob the job Will Bob get the job Bob really wants this job or some such. Can anyone here help me: 1) Come up with a phrase using Ammar's 4355 word lengths, or 2) Help me figure out how many cards would be necessary for a phrase such as "Will Bob get the job?" Thanks so much. I'm really counting on you guys (and gals). 
TomasB Inner circle Sweden 1143 Posts 
Ammars?
Anyway, at each stage when the packet has N cards you need a word of length (N1) + mN where m is an integer >= 0. So for a five card packet "Bob's the right man" would work. /Tomas 
bobmcmathman New user Arizona 43 Posts 
Thanks, TomasB
Ammars as in Michael Ammar's? Business card magic? I'm not following your formula, however. For "will the cards match?" the N would be 5,4,3 and 2 as each card is eliminated. I'm not sure how you choose m, but I know for the same series the value of [(n1)+mN] is equal to 4,3,5 and 5 for the phrase "will the cards match." Simple algebra then tells me that m was 0,0,1 and 5 at each step, respectively, but how did you get that? In other words, How can I know at each step, given N cards left, what length words will work? PS: I like your phrase "Bob's the right man," but do you think I'd be pushing it to use "Hire Bob right now!" 
rgranville Elite user Boston area 462 Posts 
Bob,
The trick has been around forever  it certainly predates Ammar's presentation with business cards  which does NOT take away from Ammar's presentation in any way. Anyway, to answer your question, it doesn't matter what value you pick for m  as long as it's an integer (no fractions). so let's say you're starting with five cards. So n = 5 and n  1 = 4. We know a word of 4 letters will work. Using the formula (n  1) + mn, that means m is 0. But what if m = 1. Then we have (5  1) + (1 x 5) = 9. Yes, a 9 letter word will work as well as a 4 letter word. Try it for yourself. And the same is true if m = 2. (5  1) + (2 x 5) = 14, and a 14 letter word also works  mathematically that is. Try a 14 letter word and you'll see eyes glaze over in your audience... And of course, after you eliminate a pair, you have 4 cards in each packet, so n = 4. But it still doesn't matter what m is equal to. For those who care, this is modulo arithmetic. As for how aggressive you should be, that's something you have to decide for yourself, based on how the rest of the interview has gone and how you believe the people interviewing you will react. And a final aside to my fellow math geeks here: Yes, I know the parentheses I used are superfluous due to associativity and the fundamental order of operations. But I thought their use makes the presentation clearer to nongeeks. :banana: 
bobmcmathman New user Arizona 43 Posts 
Thanks, rgranville
I think I see it now. I read somewhere else that this idea originated with Larry Becker. Does that sound right? 
Bob_Hummer Special user 836 Posts 
This is a lovely effect  It always seemed to me to be tangentially related to The Gilbreath Principle  And I stress the word tangentially!
There are some nice variations of this effect published in 'Apocalypse' magazine... 
Harry Lorayne V.I.P. New York City 8496 Posts 
Just for the record: Larry Becker's Will The Cards Match became popular shen I published it in APOCALYPSE so many years ago. Ammar had NOTHING to do with it.
[email]harrylorayne@earthlink.net[/email]
http://www.harrylorayne.com http://www.harryloraynemagic.com 
tltq Regular user east coast 154 Posts 
Quote:
On 20070430 13:00, bobmcmathman wrote: This may not help the original poster , but I will post it anyway Good job by Bob Will Bob amaze customers Will Bob boost sales 
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