

Papa Legba Special user homean unremarkable spiral arm of an insignificant galaxy 750 Posts 
I am trying to work on an effect in which the volunteer may lie. For example, suppose we have 8 options requiring 3 cards. Instead of answering truthfully the volunteer lies. Let's say the target number is 6, if they lie the outcome of the answers is 9 (an out of range and thus impossible number) simply subtract from 15 to get 6. My problem is this breaks down for the numbers 7 and 8. You will not know if they lied or not. Anyone have an inkling how to solve this?
Use the FORCE Luke.

saxonia Regular user 173 Posts 
I am afraid your approach cannot be understood without more details and one or two examples.

Papa Legba Special user homean unremarkable spiral arm of an insignificant galaxy 750 Posts 
Thanks saxonia, I have worked it out, not as difficult as I thought. It's basically the old binary 'age'/'computer' cards but the volunteer is able to lie.
Use the FORCE Luke.

FreddieLeeFroth New user 50 Posts 
Are you aware of the work of Leo Boudreau? That might be helpful to you in finding methods for this type of effect.

Papa Legba Special user homean unremarkable spiral arm of an insignificant galaxy 750 Posts 
Quote:
On Dec 15, 2023, FreddieLeeFroth wrote: Thanks Freddie, yes I am aware of Leo's work and I have now resolved my difficulty (much easier than I thought actually). Also I did not realise that 'Magical Equations' was an open forum, will have to take care what I ask about in future.
Use the FORCE Luke.

The Magic Cafe Forum Index » » Magical equations » » Lie detector using Binary (1 Likes) 
[ Top of Page ] 
All content & postings Copyright © 20012024 Steve Brooks. All Rights Reserved. This page was created in 0.01 seconds requiring 5 database queries. 
The views and comments expressed on The Magic Café are not necessarily those of The Magic Café, Steve Brooks, or Steve Brooks Magic. > Privacy Statement < 